Use Veency and iTunnel.exe to VNC connect to your iphone with no wifi

[johnhermie11]

hey guys! I tried everything in this thread, but all I get is bind error. What does it mean?! THanks

[potaholik]

Well ive tried TightVNC and RealVNC and both give me the same error

AMDeviceNotificationSuscribe = 0
iPhone attached!
AMDeviceConnect = 0
AMDeviceIsPaired = 1
AMDeviceValidatePairing = 0
AMDeviceStartSession = 0
MobileDevice: _send_message: could not encode message as XML
AMDeviceStartService = 0
AFCConnetcionOpen = 0

ive tried putting my itunesmobile.dll into the itunnel folder and running it in cmd.

does anyone know what this send_message file is? ive looked for it on my phone, but cant seem to find it. Thin its in the itunes.dll?

Thanks for any help

[pimpinpapoii]

ok guys.. thanks to marcan over at his website, I am finally able to VNC into my iPhone via USB (tethered). (did not use iTunnel)

I am currently running an iPhone 3GS on 3.1 firmware with iTunes 9.0.3.

for those who are still interested in VNC'ing into your iPhone via USB and are not able to, perhaps I can help a little. I spent countless hours at work trying to use iTunnel with no success. the least thing that I can do is help someone that is going through the same struggles.

BTW: I have tested with XP 32-bit, and Vista 64-bit. (both successful)

[pimpinpapoii]

Update: I can also WinSCP (OpenSSH)via USB using this method as well.

[btate0121]

Thanks but I didn't see anything at that website that helped accomplish a VNC connection to the iPhone. Perhaps I'm just not familiar enough with what I'm looking at but it looks like linux info.... which itunes doesn't run on to begin with... sooooo...

a little more info please?

[pimpinpapoii]

Sorry I took so long, I have been with out my laptop this past weekend and was not able to reply.

Anyways, Here it goes:


Considering you already already have a VNC viewer on your PC and Veency installed on your jailbroken iPhone, you will need to download the following:

- Python 2.6.x (grab the latest Python 2.6.4 Windows installer. Click Here!)

- usbmuxd 1.0.2 (usbmuxd 1.0.2)

(Unzip the file and extract to the directory of your choice.) Since we are not using Linux, we will only be using the python-clientdirectory. I extracted to the root C: directory because it is easier for me to find.

Note: The following directions reflect having downloaded both files above to your root C: directory. You can save in the files in any directory you wish to, however you will need to change the DOS commands to your need.

Edit Poseidon: When cutting and pasting the above commands into your CMD promnt you MUST delete the blank space between the colon and the \ in order for it to work.

That being said:

Open a CMD screen and use the following....

cd C: \usbmuxd-1.0.2\python-client

c: \python26\python.exe tcprelay.py 5900


If you have followed all the instructions carefully, you should then get the following message:
"Forwarding local port 5900 to remote port 5900"


Start up your VNC client, and use the 127.0.0.1 address.

You should now be able to connect to localhost using VNC.

Please remember:
iTunes must be installed and the iTunes mobile device helper must be running.3

Let me know if this works for you.

[Gabe2385]

That one worked being trying to get this for months but finally this fixed it!

Thanks
Gabe

[potaholik]

Hey just tried using pimpims method to no avail

it gives me this error everytime i try

Waiting for devices...
Connecting to device <MuxDevice: ID 7 ProdID 0x1292 Serial 'fe6d8294a6395f1cb31f
0a0024bc6ea5ec3aeb36' Location 0x0>
----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 3771)
Traceback (most recent call last):
File "CPython26\lib\SocketServer.py", line 281, in _handle_request_noblock
self.process_request(request, client_address)
File "CPython26\lib\SocketServer.py", line 307, in process_request
self.finish_request(request, client_address)
File "CPython26\lib\SocketServer.py", line 320, in finish_request
self.RequestHandlerClass(request, client_address, self)
File "CPython26\lib\SocketServer.py", line 615, in __init__
self.handle()
File "Cusbmuxd-1.0.2\usbmuxd-1.0.2\python-client\tcprelay.py", line 82, in h
andle
dsock = mux.connect(dev, self.server.rport)
File "Cusbmuxd-1.0.2\usbmuxd-1.0.2\python-client\usbmux.py", line 235, in co
nnect
return connector.connect(device, port)
File "Cusbmuxd-1.0.2\usbmuxd-1.0.2\python-client\usbmux.py", line 206, in co
nnect
raise MuxError("Connect failed: error %d"%ret)
MuxError: Connect failed: error 3
----------------------------------------

Does anyone kno how to fix this?

thanks

[Poseidon79]

That worked great! Thanks

[pimpinpapoii]

You're welcome, guys!!

I had been trying for weeks and did not want to give up. lol

finally got it.

@potaholik: you must be doing something wrong. are you changing the directory before running the python.exe command?

[potaholik]

I put everything in c:/. Ran it exactly as in your post, and got the fowarding local port MSG, but when I connect with real vnc or tight vnc and I get that message on the cmd prompt

[btate0121]

this works great. Thanks Pimpin (and lolz at the google that for you... you got me). This way actually seems more responsive (faster) than the original way (itunnel) but maybe it's just me.

as an FYI

You can take both of those commands...

cd cusbmuxd-1.0.2\python-client

cpython26\python.exe tcprelay.py 5900

paste them into a txt document and change the txt extension to .cmd and you've got yourself a one click solution to running the cmd prompt and commands. Even better if you toss it onto the quicklaunch/taskbar.

thanks again.

[sgaggerj]

Using Win 7 x64 Ultimate I'm getting the following:
using python 2.6.4

>python tcprelay.py 5900

Forwarding local port 5900 to remote port 5900
Traceback (most recent call last):
File "tcprelay.py", line 135, in <module>
server = serverclass((HOST, lport), TCPRelay)
File "CPython26\lib\SocketServer.py", line 400, in __init__
self.server_bind()
File "CPython26\lib\SocketServer.py", line 411, in server_bind
self.socket.bind(self.server_address)
File "<string>", line 1, in bind
socket.error: [Errno 10013] An attempt was made to access a socket in a way forbidden by its access permissions

I've run an admin cmd prompt and disabled my firewalls. any suggestions?

[kchan069]

Anyone got it working using Mac OSX according to the instructions posted with the use of USBMU and PYTHON 2.6.4 ? i tried it in WinXP and it worked fine, just wondering if i can do the same for my mac. Thanks!

[showstopper]

I know this is an old thread but has anyone got itunnel to work in windows 7? I have it all working at work which is windows xp but at home on windows 7 no luck.

Is there any other software that will allow me to SSH via usb?

[potaholik]

I use ifunbox to ssh into my iPhone through USB

[showstopper]

I use ifunbox to ssh into my iPhone through USB

Cheers for that. Works well.

[pimpinpapoii]

this works great. Thanks Pimpin (and lolz at the google that for you... you got me). This way actually seems more responsive (faster) than the original way (itunnel) but maybe it's just me.

as an FYI

You can take both of those commands...

cd c:usbmuxd-1.0.2python-client

cython26python.exe tcprelay.py 5900

paste them into a txt document and change the txt extension to .cmd and you've got yourself a one click solution to running the cmd prompt and commands. Even better if you toss it onto the quicklaunch/taskbar.

thanks again.

you're welcome. My friend got me with the google thing, and I was waiting for an opportunity to use it...... lol

Using Win 7 x64 Ultimate I'm getting the following:
using python 2.6.4

>python tcprelay.py 5900

Forwarding local port 5900 to remote port 5900
Traceback (most recent call last):
File "tcprelay.py", line 135, in <module>
server = serverclass((HOST, lport), TCPRelay)
File "C:Python26libSocketServer.py", line 400, in __init__
self.server_bind()
File "C:Python26libSocketServer.py", line 411, in server_bind
self.socket.bind(self.server_address)
File "<string>", line 1, in bind
socket.error: [Errno 10013] An attempt was made to access a socket in a way forbidden by its access permissions

I've run an admin cmd prompt and disabled my firewalls. any suggestions?

I have never tested on W7. I will try today and let everyone know.

[xXrkidXx]

Sorry I took so long, I have been with out my laptop this past weekend and was not able to reply.

Anyways, Here it goes:


Considering you already already have a VNC viewer on your PC and Veency installed on your jailbroken iPhone, you will need to download the following:

- Python 2.6.x (grab the latest Python 2.6.4 Windows installer. Click Here!)

- usbmuxd 1.0.2 (usbmuxd 1.0.2)

(Unzip the file and extract to the directory of your choice.) Since we are not using Linux, we will only be using the python-clientdirectory. I extracted to the root C: directory because it is easier for me to find.

Note: The following directions reflect having downloaded both files above to your root C: directory. You can save in the files in any directory you wish to, however you will need to change the DOS commands to your need.

Edit Poseidon: When cutting and pasting the above commands into your CMD promnt you MUST delete the blank space between the colon and the in order for it to work.

That being said:

Open a CMD screen and use the following....

cd C: usbmuxd-1.0.2python-client

c: python26python.exe tcprelay.py 5900


If you have followed all the instructions carefully, you should then get the following message:
"Forwarding local port 5900 to remote port 5900"


Start up your VNC client, and use the 127.0.0.1 address.

You should now be able to connect to localhost using VNC.

Please remember:
iTunes must be installed and the iTunes mobile device helper must be running.3

Let me know if this works for you.

Your a genius. It works perfectly!

Thank you so much!

[brbell01]

I cant seem to get this to work on a windows machine. usbmuxd doesnt seem to be a windows executable. Any ideas?