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  1. #1
    What's Jailbreak?
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    Default Send command to iPhone without openSSH

    hi iPhone deverloper,

    i wonder if i could send any command to iPhone from PC without openSSH, such as reboot command.

    i dont know iTunesMobileDevice.dll provice this function or not. refference some program on Window for example : iPhuc, iphoneinterface.exe, but it couldnot reboot iPhone.

    looking forward your help!

  2. #2
    iPhone? More like MyPhone BoneCrif's Avatar
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    you could use MobileTerminal, which is installed on the iPhone.
    it's just basically a terminal on the iPhone.
    8GB iPhone 2G
    3.1.2 - Unlocked and Jailbroken

    AMD Athlon 5000 Dual-Core 2.2GHz with 4.00 GB RAM
    Windows 7 Ultimate 64 bit

  3. #3
    What's Jailbreak?
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    i Knew that, but i want to send command from PC, because i'm develop a application on Window to erase all personal data, then i want to send command "reboot" iPhone and check i again to ensure all personal data to be erased.

    Thank for your help!

  4. #4
    Moderator Admin Broomhead's Avatar
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    you could try diskaid. I'm not sure it will do what you want, but worth a try. It connect through the USB cable.
    http://www.modmyi.com/forums/iphone-...-100-free.html
    DiskAid - Transfer Files betwen your Computer and your iPhone or iPod Touch. Disk Mode for your iPhone and iPod Touch.

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    HunterIP (03-05-2009)

  6. #5
    Developer/Hacker JStraitiff's Avatar
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    if you can figure out how diskaid uses usb you can just write it into your program so instead of connecting via SSH it will use diskaid's method

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    HunterIP (03-05-2009)

  8. #6
    What's Jailbreak?
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    Thank for your all reply,

    DiskAid for USB file transfer is same iPhoneList or iPhonebrowse software, it only provice some tools to access file from PC, copy file to and from iPhone, delete file on iPhone ... not could be send "reboot" command.

    My program complete erase all personal data, it consist of Game, Application (not original Apps), contact, message ... but i could "reboot" my iPhone. it is too difficult.

    pPlease give me solution (

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