
Originally Posted by
esherman
I tried to jailbreak my 3GS running 4.2.1 (using redsn0w 0.9.6b4) and it initially worked great. Then I installed some apps from cydia and tried to reboot with redsn0w (I have the new bootrom, so it's tethered) but it had an unexpected error and crashed. Through several restores via iTunes, I was able to get a functional phone again, however there is a problem.
1) it's unjailbreakable - redsn0w just says "unknown error" and the phone's screen goes blank when I try to install cydia or "just boot tethered right now." The only way to get a usable phone again is to restore through iTunes
2) i seem to have managed to install two, yes two copies of iPhone firmware on my phone. When I plug it in to iTunes, it shows up as two phones - one that is working fine (I can sync, play music off of it, etc.) and one that's in recovery mode. The working copy has 1GB of space occupied by "Other" which I presume is the defunct install of firmware? When I try to restore the recovery mode one it gives error 1601. Interestingly, when I restore one of the phones, both phone icons in iTunes indicate that their respective phones are being restored, when in reality, I only hit restore for one of them.
I assume my two problems are linked and that if the defunct install is removed, then redsn0w will be able to grab on the the correct install and jailbreak/boot tethered. How can I get rid of this other install? I know the 3GS has hardware encryption, so a remote wipe just trashes the encryption key - is this enough to destroy the phone (both installs included) and start from scratch, or does each install of iOS have it's own key so that a remote wipe would just kill the functioning copy and leave the defunct copy alone?
Thanks (and sorry for any ignorance - I'm kind of a n00b)