[robbienakata]

Well i got everything i would need from radioshack today, but somehow managed to lose the resistors between there and my house... Don't know what happened there... But i could not find any 470 kOhm resistors only 470 Ohm ones. Is that what you meant to say?

[iBlade]

No no no, please be careful. 470 kOhm means 470 kiloOhm meaning 470.000 Ohm. See here:
http://www.dannyg.com/examples/res2/resistor.htm
The two pins in the middle are ttl serial data pins and can only handle 3.3v but you are charging with 5v so you have to reduce the voltage. 470ohm would not do that for you, you can damage the phone. You can use something close to 470kOhm 420-510kOhm will work. Remember going to low damage, to high phone will not accept charge.

[robbienakata]

Okay good thing I lost those resistors then! Well Im not too confident in my electronics and I've been meaning to buy one of those boxwave adapter thingies anyways to work a couple chargers I have. I'll let you know how it works. Thanks for all your help!

http://www.boxwave.com/products/ipho...phone_2661.htm

[iBlade]

You're welcome. The boxwave adapter looks alright, at least it is easier.

[robbienakata]

Okay got my adapter today. Everything works great. I'd post pictures but it looks pretty identical to yours. Thanks for all your help!

[Rivest]

Well I just tried it but it didn't work. Not even my ipod nano charges. I surely did something wrong. I used Yellow-Purple-Yellow resistor. Here's what I made :

[diazjoaquin]

http://cgi.ebay.com/2200mAh-EXTERNAL...QQcmdZViewItem


Iam using this one and I love it, it works great its a must have..

[robbienakata]

So I've run into an issue. Once the batteries are drained from the pack it seems to suck the juice out of my phone. Would a simple diode fix this problem?

[julianqm2]

i like the 3rd one

[iBlade]

Originally Posted by robbienakata

So I've run into an issue. Once the batteries are drained from the pack it seems to suck the juice out of my phone. Would a simple diode fix this problem?

Yes it would fix it. It's just that a average diode consumes about 0.7volts meaning your charging voltage drops by 0.7volts.

[Aiyo]

Ok I am going to for sure try this and I would like to try it with a diode and the resistors. Would one of you be willing to make a dummies diagram for this? Almost something like rivest's diagram, but more clear?

[Rivest]

Yeah don't follow mine because I said it didn't work. I would love to help you but I need help first

[iBlade]

Originally Posted by Aiyo

Ok I am going to for sure try this and I would like to try it with a diode and the resistors. Would one of you be willing to make a dummies diagram for this? Almost something like rivest's diagram, but more clear?

Check my post number 11 on page one. If you want to use a diode also just splice it into the positive (red) wire comming from the battery pack. The diode is directional meaning only lets current flow one way. You have a stripe on the diode on one side that side has to be on the phone side.
Plus from the battery ------[___I_]------going to the usb plug.

[Rivest]

Yeah! I got it working using the diagram on the first page. Thanks to everybody who helped

[Aiyo]

Hmm only if we could do this so it would go straight into the 30pin..