Openurl Problem

[jayzhuo]

if the user-defined url containts '?', openurl will interpret the '?' as '%3F' and open the url in safari. Safari does not understand the '%3F'. It will result in a "Page Not Found" error!

Is there any solution for this problem currently?

[CVB]

This is tweaked from Erica's open url app.... I was able to open all sorts of urls that contained %?#@ etc...

- (void) applicationDidFinishLaunching: (id) unused
{
	[self openURL:[NSURL URLWithString:@"http://someurl.com?q=asdf%?1234etc"]];
}

Erica's app used initFileURLWithPath instead of URLWithString.